The following is a view of the Claims structure. How to calculate DateDiff in minutes correctly?Im using this: update client_invoices set x6 = datediff(x4, date_due) as an event in mysql but everytime they updates the server the "Event scheduler status" is turned off. The int data type takes 4 bytes as storage size whereas bigint. This is because it only compares the date values (it ignores any time values). SparkSQL - Difference between two time stamps in minutes. TIMESTAMPDIFF ( numeric-expression string-expression. The T-SQL DATEDIFF is defined as a primary function in T-SQL that can be used to find the difference between two date-utilities in which it has been utilized to differentiate between two date values having various date parts. Sql server supports adding and subtracting on Datetime data type, so you can simply do something like this: DECLARE @StartTime datetime = '2016-05-10 02:25:34. SQL Server: -- Get difference in days SELECT DATEDIFF(dd, '2022-09-01', '2022-09-05'); # 4By default, MySQL TIME fields allow a time range of '-838:59:59' to '838:59:59'. -- Select [dbo]. The calculation is correct, and the output is easily interpretable. SQL Server: -- Difference between Oct 02, 2011 and Jan 01, 2012 in years SELECT DATEDIFF (year, '2011-10-02', '2012-01-01'); -- Result: 1. 4 Answers. We can get the difference in any type of datepart format like difference in days, month, year and etc. To calculate the difference between the timestamps in Oracle, simply subtract the start timestamp from the end timestamp (here: arrival - departure ). SQL Server added the LAG and LEAD functions in T-SQL to help find a previous record related to the key fields. The schema is SYSIBM. 677', '2021-02-17 20:52:51. You get the difference in days. forexData AS T WHERE T. startdate and enddate have to be in a format. Time difference (Seconds) = DATEDIFF ( SalesData [OrderDate 2], SalesData [ShipDate 2], SECOND ). Mangu. The second parameter of DATEDIFF takes a datetime so your string is implicitly converted to a datetime. DATEDIFF : DATEDIFF_BIG : This is a very old function and it is available from the initial release SQL Server. Datediff SQL is a pivotal function for developers, enabling precise calculations between two dates. ) and rest are two dates which you want to compare. 0. I used your SQL Fiddle and posted a working solution here. In SQL Server: Like we do in SQL Server its much easier. Then , I searched about MariaDB's DATEDIFF and I saw this , I figured out. enddate: The ending datetime value. datediff (to_date (String timestamp), to_date (String timestamp)) SELECT datediff (to_date ('2019-08-03'), to_date ('2019-08-01')) <= 2; to_date is unnecessary if the column is already in 'yyyy-mm-dd' format. The DATEDIFF function will return the difference count between two DateTime periods with an integer value whereas the DATEDIFF_BIG function will return its output in a big integer value. column. TIMEDIFF(time1, time2) 差分の時間は time1 - time2 で計算されます。. SQL Reference. date_part is the part of date e. In SQL Server: Like we do in SQL Server its much easier. In case you use a DATE value, the TIMESTAMPDIFF function treats it as a DATETIME value whose time part is. Returns the difference between two timestamps measured in unit s. Problem: You have two columns of the date type and you want to calculate the difference between them. The SQL DATEDIFF function calculates and returns the difference between two date values. SQL Server 2012 : DATEDIFF function in terms of years, days and months. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest,. Overview: I have tables SHIFT_LOG, SHIFT_LOG_DET & SHIFT_LOG_ENTRY having Parent-Child-GrandChild relationships (one-to-many). Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. hàm datediff. 4. If you want the value as an exact figure (or nearabouts), you should datediff the dates on days, then divide by 30. This function allows you to obtain data from the previous record (based on an order criterion, which here is “ ORDER BY year ”). Follow. Quick Example : -- The difference is days between today and yesterday SELECT DATEDIFF ( dd , GETDATE ( ) - 1 , GETDATE ( ) ) ; -- Returns: 1 -- The number of seconds in 24 hours SELECT. That will give you the average differences for each distinct value of col1. Here's what that query would look like in Navicat: To convert the rental_date from a datetime to a pure date we can use the DATE () function. The next example will show the differences between two dates for each specific datapart and abbreviation. Calculates the difference in week numbers and year numbers, subtracts the week numbers and then multiplies the result by 2 to calculate number of non-workdays between the two dates. 53. Edit the SQL Statement, and click "Run SQL" to see the result. time2: The second TIME or DATETIME value. Update2. CREATE TABLE working_hours (start DATETIME, end DATETIME); Now populate the working hours table with countable periods, ~250 rows per year. ). The datepart passed to DATEDIFF will control the resolution of the output. But CONVERT() isn't a good solution for this. SELECT DATEDIFF(MINUTE,job_start,job_end) MINUTE obviously returns the difference in minutes, you can also use DAY, HOUR, SECOND, YEAR (see the books online link for the full list). For example: the difference between 20180115 to 20180220 is 36 days. date, c2. I) if you need to calculate the elapsed time in seconds between two timestamp columns try this: SELECT extract ( day from (end_timestamp - start_timestamp) )*86400 + extract ( hour from (end_timestamp - start_timestamp) )*3600 + extract ( minute from (end_timestamp - start_timestamp) )*60 + extract ( second from (end_timestamp - start. No longer do you need to use temporary tables although using staging tables for further calculation could be required. 0. Where a. Here is a SQL script to demonstrate:Luckily, there’s a handy DATEDIFF function that can do that for you. functions val df2 = df1. Note that the syntax for datediff () uses the SQL Server version of the function. Arguments. datediff between multiple records in SQL. This is a very old question and your answer doesn't really answer the same. Also, you can swap out the 'd' character for other dateparts, say if you wanted to find the date difference in months, years etc. The DATEDIFF function results are truncated, not rounded, when the result is not an even multiple of the date part. 在 SQL Server 中，我們可以用 DATEDIFF() 函數取得兩個日期之間相差的時間間隔。 DATEDIFF() 語法 (Syntax) DATEDIFF(datepart, startdate, enddate) DATEDIFF() 執行後會返回一個正負樹的整數，表示 enddate - startdate 的時間間隔，datepart 參數則用來指定返回值. T-SQL - Seconds per hour between two datetimes across 2 dates. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. In this, we will add the number of years that we expect this person to turn in a given year, based on the DATEDIFF( ) results. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. . Weeks, quarters, and years follow from that. Parse [ ^] to parse it. Calculating the difference between two dates or times in DB2. DECLARE @NumberOfSeconds int SET @NumberOfSeconds = 3843 -- 1 hour, 4 minutes, 3 seconds SELECT @NumberOfSeconds AS 'seconds', CONVERT (varchar, DATEADD (second,. Syntax. If you really want 'datediff' in your database, you can just do something like this: Now, i just create a view to demonstrate with: SQL> select datediff ( 'ss', d1, d2 ) seconds from temp_view; SECONDS6269539. There aren't any duplicate entries in terms of time, the minimum time difference. Difference in minutes from two time fields in MySQL. Bid) AS Diff FROM dbo. Spark & PySpark SQL provides datediff() function to get the difference between two dates. Q&A for work. There are a number of ways to look at a date difference, and more when comparing date/times. In case you use a DATE value, the TIMESTAMPDIFF function treats it as a DATETIME value whose. 25 then it will return number of years in decimal places. The function counts whole elapsed units based on UTC with a DAY being 86400 seconds. SQL Server DATEDIFF() 日期相減. However I want the output to be formatted as:If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. (note that DateDiff, as referenced by @Christoph, does exist, but you can just as easily use the substraction operator -) CDate(Abs([Time] - [MapOriginalStart])) Note that you will probably run into trouble because you're probably not understanding time in Access properly. Subtracting a later time '23:59:00' from an earlier time '00:53:00' obviously gives a negative value -230600. These functions can be used in SQL Server queries to perform various date and time operations, such as filtering records based on dates, calculating date differences, and formatting. 5 = Thursday. SQL Server added the LAG and LEAD functions in T-SQL to help find a previous record related to the key fields. If TIMEDIFF() returns -02:00:00, -00:05:00, or 00:04:00, then the record would. Date, S. After executing you can use it like this. mysql Timediff() function returns 0. Using timestamp column value in TIMEDIFF function. The results are limited to TIME values ranging from - 838:59:59 to 838:59:59. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual;. Learn more about Teamsmysql的时间差函数timestampdiff、datediff的用法时间差函数timestampdiff、datediff的用法我们在写sql语句，尤其是存储过程中，会频繁用到对于日期、时间的比较和判断，那么对于这两个时间差比较函数用法做一个举例介绍。引数. The following is a view of the Claims structure. Finding the seconds difference can be done as follows: SELECT (mod_date_time - create_date_time) * 24 * 60 * 60 as "seconds_diff" FROM t1. Timediff() The timediff(A,B) routine returns a string that describes the amount of time that must be added to B in order to reach time A. DECLARE @date datetime2 = '2021-01-07 14:36:17. Definition, syntax, examples and common errors using BigQuery Standard SQL. In MySQL, the TIMEDIFF () function is used to return the difference between two time or DateTime components. The SQL DATEDIFF () function is an in-built function in SQL that is used to return the difference (as a signed integer value) between two dates or times. 2425):DateDifference 1 73:12:30. count will count all non-null values, so for else return NULL instead of zero. 677', '2021-02-17 20:52:51. Calculating age at time of an event in SQL. The following shows the syntax of the DATEPART() function:. If only a date value is assigned to a variable of a time or date data type, DATEDIFF sets the value of the missing time part to the default value: 00:00:00. format_datetime(timestamp, format) → varchar. 1 year and 2 months. datepart DATEDIFF で startdate と enddate の違いを報告する場合の単位。 一般的に使用される datepart の単位には、month または second が含まれます。. 1 : Fractions of a second. I would expect select CONVERT (varchar (12), DATEADD (SECOND, DATEDIFF (SECOND, '2021-02-16 18:41:31. count week days in sql by datediff. 0. functions. Example 5: Use Current Date. If year numbers are different calculation of 52 * year difference + week number. DATEDIFF(hour, start_date, end_date) will give you the number of hour boundaries crossed between start_date and end_date. For SQL Server, if you're sure that the difference is less than 24 hours, you can use timefromparts to get the difference as a time data type. SELECT DATEDIFF (day, '2019-12-05 08:09:55', GETDATE ()); Result: 39. id = t2. If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result: DATEDIFF(second, start_date, end_date) / 3600. 2 Answers. You can use the DATEDIFF function to get the difference in minutes, seconds, days etc. A Microsoft extension to the ANSI SQL language that includes procedural programming, local variables, and various support functions. The WEEK_OF_YEAR_POLICY session parameter controls how the WEEK and YEAROFWEEK functions behave. it returns the difference in days if datepart is day. TIME_TO_SEC only converts the time section so you end up with big negatives if the clock goes past midnight. Columns. Well in SQL Server GETDATE() is Equivalent to CURRENT_TIMESTAMP. This will give you the difference in days. Edit the SQL Statement, and click "Run SQL" to see the result. datediff() 今回は日付ではなく分単位だったため; subtime() 動きそうだと思ったけど null が返却された; 使えそうなもの. SELECT id, timeIn, timeOut, TIMEDIFF ( timeOut, timeIn ) AS timeDifference FROM table WHERE TIMESTAMPDIFF ( SECOND, timeOut, timeIn ) > 180000; This statement will output the fields for each record where the difference between the two timedates is one second or more over 50 hours (or 180000 seconds ). 1. The TIMESTAMPDIFF function allows its arguments to have mixed types e. Here’s the syntax of TIMEDIFF() function: TIMEDIFF(time1, time2); Code language: SQL (Structured Query Language) (sql) In this syntax: time1: The first TIME or DATETIME value. Abbrevations. In Access, 12:51 AM is equal to 00:51 AM. With the birth of SQL Server 2016, Microsoft has introduced a new DATEDIFF SQL function, an enhanced version of DATEDIFF known as DATEDIFF_BIG. What MySQL function can I use to get the difference in hours of the two date time strings? I tried DATEDIFF(sql timediff function. In most cases, though, what you really want is the number of days from the first date to the second date. ), the start date or time that specifies the beginning of the period. In MySQL, you can use the DATEDIFF() function to find the difference between two dates. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. Below would correct the most popular answer to return hours as an integer and minutes as a decimal (ie 6. Alternativa para DATEDIFF. , a year, a quarter, a month, a week that you want to compare between the start_date and end_date . Share. 8. 0. You can see in the above example – both of them returns the same value. Example: In the travel table, there are three columns: id, departure, and arrival. Date Part Intervals. This example uses the DateDiff function to display the number of days between a given date and today. datediff (timestamp) function. Also stop using lazy shorthand like DATE1 - DATE2 (it doesn't work with the data types you should be using since SQL Server 2008). The TIMESTAMPDIFF function returns the result of begin - end, where begin and end are DATE or DATETIME expressions. Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. sql. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. However, if you use CURRENT_TIMESTAMP in your select statement it will work fine. Something like: SELECT DATEDIFF (d, StartDate, EndDate) FROM tableName. 2 Answers. FROM MyTable. 0 would return 0, but DATEDIFF(second, start_date, end_date) / 3600. sql. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. Run SQL ». I'm trying to convert the difference in minutes between two timestamps in the form MM/dd/yyyy hh:mm:ss AM/PM. Use UNIX_TIMESTAMP instead to do the sum. Improve this answer. Note: time1 and time2 should be in the same format, and the calculation is time1 - time2. If you want the value as an exact figure (or nearabouts), you should datediff the dates on days, then divide by 30. If start is greater than end the result is negative. Follow edited May 15, 2018 at 17:24. In this case, the enddate is arrival and the startdate is departure. For example, you can use: SELECT TIMESTAMPDIFF (SECOND, '2012-06-06 13:13:55', '2012-06-06 15:20:18') In your case, the third parameter of TIMSTAMPDIFF function would be the current login time ( NOW () ). endDate: A DATE expression. In your case PHP. NOTE: This code shows that you cannot go past 24 hours in a time; it just wraps back around (with no error!): declare @FirstTime time (7) SET @FirstTime = '23:05' print @FirstTime Set @FirstTime = DATEADD (HOUR,1,@FirstTime) print @FirstTime. The DATE type is oldest (it was in the precursor to the SQL-based Informix), and represents the integer number of days since a reference date (where day 0 is 1899-12-31, so day 1 was 1900-01-01). In Calculating Work Days you can find a good article about this subject, but as you can see it is not that advanced. Calculates the difference in days between the two dates. Sintaxis. 5. This function takes three arguments: the start date, the end date, and the unit of time you want to measure. The part can be the day of the date, month of the date, year of the date etc. Posted 1-Mar-15 0:14am. timediff¶. SELECT DATEDIFF(end_date, start_date) from accounts But, I don't know how am I supposed to do it in MySQL, I found this article Count days between two dates, excluding weekends (MySQL only) . numeric-expression. Edit the SQL Statement, and click "Run SQL" to see the result. . FirstName + ' ' + Users. Below is the syntax for the DATEDIFF () function to find the no. DATEDIFF uses the following cutoff points to calculate those intervals:. Hope it helps. If you are using Sql Server 2012+ then use. Q&A for work. The Technet article details the return value of the DateDiff Function - note that it's only int. 0. Returns the difference between two timestamps measured in unit s. DATE () Extract the date part of a date or datetime expression. it returns the difference in days if datepart is day. 0. The format of the timediff() result is designed to be human-readable. My time stamps are down to the milisecond. ; int dayDiff = (endDate - startDate). datediff(yy,'31 Dec 2013','1 Jan 2014') returns 1. To calculate the difference between two dates, you use the DATEDIFF () function. #. select (test_time - sysdate)*24*60 from test; This value is negative if test_time is lies in. That prevents SQL Server from using. mySql TimeDiff between TimeStamp in Rows of a Single Table. 0 indicates weak or no similarity between the SOUNDEX values. UserID ORDER BY Feeds. 5 hours). MySQL TIMEDIFF() With Large Values. g. You can put the above code in a method that you can call from your LINQ query. Now it only runs DateAdd () once, and it can use an index (if one exists), to only load the rows that match the predicate criterion. Timediff in MySQL wrong values. In a Unicode database, if a supplied argument is a. TIMEDIFF () is useful for filtering records or data based on time criteria, such as selecting records within a specific time range. round ( 48 * ( cast (ActualEnd as float)-cast (ActualStart as float) ),0) /2. The datepart argument can be microsecond, second, minute, hour, day, week, month, quarter, or year. For example, only seconds, or only minutes or only hours. The TIMESTAMPDIFF function returns the result of begin - end, where begin and end are DATE or DATETIME expressions. MS Sql Datediff Function. Applies to: SQL Server 2016 (13. For neatness, I've also rounded to. If the returned result is out of range for 32-bit. All of this is well documented in MySQL Date and Time functions. 較舊的日期減較新的日期會得到負數：. AT TIME ZONE. SELECT datedifference (date1,. This function accepts three parameters − the type of interval to measure (such as year, quarter, month, hour, minute, etc. Use the DateDiff function in VBA code. The datepart argument can be microsecond, second, minute, hour, day, week, month, quarter, or year. Difference between two dates returned in hours,minutes,seconds. Pair, S. It can be used to do date math as well. Following is the syntax of the above function – TIMEDIFF(expr1, expr2) Example 1 DATEDIFF returns the total number of the specified unit between startdate and enddate. USER_FECHA_INCORPORACION, AGENTE. SQL Server DATEDIFF() 函数 SQL Server Date 函数 定义和用法 DATEDIFF() 函数返回两个日期之间的天数。 语法 DATEDIFF(datepart,startdate,enddate) startdate 和 enddate 参数是合法的日期表达式。datepart 参数可以是下列的值： datepart 缩写 年 yy, yyyy 季度 qq, q . UserID = Users. 0000. The best will likely be: SELECT <column list> -- not * (1) FROM dbo. This does it in days: select username, avg (end_date - start_date) as avg_days from mytable group by username. 166k 39 234 307. TIME_DIFF function. enddate)) AS timediff FROM MYTABLE t GROUP BY t. The TO_DAYS () function returns the number of days between a date and year 0 (date "0000-00-00"). Cú pháp sử dụng hàm DATEDIFF () Hàm DATEDIFF () được sử dụng để kiểm tra sự khác biệt giữa hai khoảng thời gian, cú pháp của hàm DATEDIFF () như sau: DATEDIFF(interval, date1, date2) Tham số: interval là khoảng sử dụng. If you want the result in days/hours/minutes you can use modulus division:1 Answer. The DATEPART() function returns an integer which is a part of a date such as a day, month, and year. TIME TIMEDIFF (DATETIME expr1, DATETIME expr2) TIMEDIFF returns the difference between two DATETIMEs. g. 0. I know there is one inbuilt function DATEDIFF for this but i want some custom fractional difference like: sDate. Timediff in MySQL wrong values. 0. The value returned is an integer. e. 0. Another example is to get the month of a. 3. Delaying Execution. 4. To do this, we need to create a calculated column using the DATEDIFF DAX function as seen in the diagram and DAX syntax below. DATEDIFF returns the count of the specified date part boundaries crossed. Time' How to repeat: ResultSet result = getConnection (). If you want to your query to return three (one for each actual date involved), either JOIN to a calendar table, add one to the result automatically, or do the datediff in hours, divide by 24. SELECT TIMESTAMPDIFF (<INTERVAL>,<timestampFrom>,<timestampTo>); If you want to find the difference between the first and the last timestamp of a given host ID, here you are: SELECT TIMESTAMPDIFF (MINUTE,MIN (pingtime),MAX (pingtime)) FROM yourTable WHERE. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(),. SQL Server Calculate during 07H00 and 23H00 during weekdays. 4 Answers. 0. The DATETIME system is newer (but still old — circa 1990). CreatedDate, DATEDIFF (DAY, a1. Hello colleagues I am trying to bring the datediff function from sql server to postgresql with date_part but I can't get it to work, it is for a search filter. I am using SQL SERVER. TIMEDIFF(date1, date2) Arguments. Return the difference between two time expressions: SELECT TIMEDIFF ("13:10:11", "13:10:10"); Try it Yourself » Definition and Usage The TIMEDIFF () function returns the difference between two time/datetime expressions. Improve this answer. If endDate is before startDate the result is negative. Specifies the first day of the week. The function returns the result of subtracting the second argument from the third argument. You can use DATEDIFF to calculate a wide variety of calendar calculation by varying the datepart parameter. For example, we can use the DATEPART function to get the day of a given date to determine whether an order was placed on Sunday or not. Returns the difference between two timestamps measured in unit s. select datediff (dd,convert (date,date2),convert (date,date1)) From Yourtable. Complete command we have used to display record is like. You get the difference in days. Invalid function type [TIMEDIFF] for window function. How to use TimeDiff function in Where clause. For example: the difference between 20180115 to 20180220 is 36 days. Plus, maybe the datediff sequence might need swapping the datetime values as you may be producing negative values, but this is data dependent so I am not certain on this latter point. 25; You might want to truncate result of above query to two decimal places. The schema is SYSIBM. You probably want to use timestampdiff () select DriverName, CarType, min (timestampdiff (second, StartTime, EndTime)) as Best, max (timestampdiff (second, StartTime, EndTime)) as Worst from followingtable ft group by DriverName, CarType; If you want to show the value as a time format: select DriverName, CarType, date_format (cast. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. SQL Server DATEDIFF Function Summary: in this tutorial, you will learn how to use SQL Server DATEDIFF () function to calculate the number of years, months, weeks, days,etc. comは、オラクル、MS-SQL、MS-Access で使用可能か一目でわかるページ. SSS This time difference string is also an allowed modifier for the other date/time functions. Passing DATEDIFF interval as user defined function argument?I came across an easier way of solving this issue. Using T-SQL DATEADD and DATEDIFF function. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. Your best bet is to calculate the difference in seconds, and use a function to format the result. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. If your data types are more precise than simply date, and instead you wanted it rounded - e. Note that SQL Server DATEDIFF function returned 1 year although there are only 3 months between dates. CAST(CURRENT_TIMESTAMP AS DATE) or DATEADD(DAY, 0, DATEDIFF. sql; google-bigquery; datediff; date-difference; Share. To calculate the difference between the arrival and the departure in T-SQL, use the DATEDIFF (datepart, startdate, enddate) function. Add 18 years to the date in the BirthDate column, then return the date: SELECT LastName, BirthDate, DATEADD (year, 18, BirthDate) AS DateAdd FROM Employees; Try it Yourself ». 1. DateDiff in SQL. numeric-expression. 1. See more linked questions. Multiply by 24 to get hours, and so on. select post_visid_high || ':' || post_visid_low as visitor_id , lag (date_time) over (partition by visitor_id order by date_time asc) as previous_date , datediff (minute, previous_date, date_time) as difference_in_minutes from adobe_data. Table 9. timestamp AS timediff FROM foo t1 inner join foo. 0. Edit the SQL Statement, and click "Run SQL" to see the result. --Changing current database to the Master database allows function to be shared by everyone. Timestamp DESC. The difference is measured in the time unit specified by datepart. Consider SQL Server function to calculate the difference between 2 dates in years: . SELECT DATEDIFF (second, '2005-12-31 23:59:59. Timestamp = DATEDIFF (MINUTE, Feeds. . In addition, with DATEDIFF () the column is an argument to the function. Here is a solution that will do that for each row: import org. DECLARE @null time; SET @null = '00:00:00'; SELECT DATEADD(SECOND, - DATEDIFF(SECOND, End_Time, Start_Time), @null) Reference: Time Difference Edit: As per the comment, if the difference between the end time and the start time might be negative, then you need to use a case statement as suchDescription. createdon) [date diff in min] FROM cte c1 JOIN cte. I need to get scenario value when timediff(c2,c3) > 30 MIN SELECT scenario, rowcreatedctime,eventtime FROM `chat_assist_session_request` LIMIT 1 scenario rowcreatedtime eventtime scen1 2014-09-02 09:00:00 2014-09-02 09:45:00 scen2 2014-09-02 10:00:00 2014-09-02 10:13:00 I would like to query a database using sql to show the difference in time between id 1,2,3 and so on. There's no built-in function - but you could relatively easily write your own T-SQL stored function to calculate this - something like this: CREATE FUNCTION. , between two dates. After executing you can use it like this. {fn TIMESTAMPDIFF (interval,startDate,endDate)} returns the difference between the starting and ending timestamps ( startDate minus endDate) for the specified date part interval (seconds, days, weeks, and so on). For an overview of all Transact-SQL date and time data types and functions, see Date and Time Data Types and Functions (Transact-SQL). SyntaxI tried with DATEDIFF but I am never able to get a true values especially for the case from 18:30 to 6:00 I tried like this, but does not work for this case(8:30 to 6:00). Difference will be calculated as startdate - enddate . 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. Improve this answer.